Pada dua bangun yang sebangun ini tentukan panjang qr?

1) AE : PT = AB : PQ
AE : 18 = 32 : 24
24.AE = 32 . 18
24 AE = 576
AE = 576 : 24
AE = 24 cm
   ED : TS = AB : PQ
ED : 21 = 32 : 24
  24.ED = 32 . 21
24.ED = 672
ED = 672/24
ED = 28 cm
  BC : QR = AB : PQ
48 : QR = 32 : 24
32.QR = 48 . 24
32.QR = 1152
QR = 1152/32
QR = 36 cm
2A) EF : AB = FG : BC
EF : 20 = 28 : 35
35.EF = 20 . 28
35.EF = 560
EF = 560/35
EF = 16 cm
HG =

=

=

=

= 20 cm
EH : AD = FG : BC
16 : AD = 28 : 35
28.AD = 16 . 35
28.AD = 560
AD = 560/28
AD = 20 cm
HG : DC = FG : BC
20 : DC = 28 : 35
28.DC = 35 . 20
28.DC = 700
DC = 700/28
DC = 25 cm
2B) X = 180° - 127°
= 53°
Y = 127°
Z = X
= 53°

makasii yaa cerdasnya kao
tank yu, now im underground wit tish

1. AB/PQ = BC/QR32/24 = 48/QRQR = 24 x 48 / 32QR = 362. A.EF = AB x FG / BCEF = 20 x 28 / 35EF = 16 cmHG = Teorema Phytagotasseandainya dari H kita buat garis lurus kebawah maka terbentuk segitiga siku-siku maka panjang HG adalah

= 20 cmAD = EH x BC / FGAD = 16 x 35 / 28AD = 20 cmDC = HG x BC / FGDC = 20 x 35 / 28DC = 25 cm2. B. Nilai x = nilai z = 180 - 27 = 53nilai y = 127